Rotational Motion and Torque — Practice Quiz
A Physics cheat sheet for Rotational Motion and Torque — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Angular Displacement: Angle \(\theta\) (in radians) is arc length \(s\) divided by radius \(r\).
Average Angular Velocity: Change in angular displacement \(\Delta\theta\) over time \(\Delta t\).
Average Angular Acceleration: Change in angular velocity \(\Delta\omega\) over time \(\Delta t\).
Rotational Kinematics (Velocity-Time): Final angular velocity \(\omega\) given initial \(\omega_0\), acceleration \(\alpha\), and time \(t\).
Rotational Kinematics (Displacement-Time): Angular displacement \(\theta\) given initial velocity, acceleration, and time.
Rotational Kinematics (Velocity-Displacement): Relates velocities, acceleration, and displacement without time.
Tangential Velocity: Linear speed \(v_T\) of a point at radius \(r\) with angular velocity \(\omega\).
Tangential Acceleration: Linear acceleration \(a_T\) of a point at radius \(r\) with angular acceleration \(\alpha\).
Centripetal Acceleration: Radial acceleration component toward the center.
Rolling Motion (No Slipping): Linear velocity and acceleration of the center of mass related to angular quantities.
Torque: The magnitude of torque \(\tau\) is the distance \(r\) from the pivot to the force \(F\), multiplied by the perpendicular component of the force.
Rotational Analog of Newton's Second Law: Net torque \(\tau_{net}\) equals moment of inertia \(I\) multiplied by angular acceleration \(\alpha\).
Moment of Inertia (Point Masses): The moment of inertia \(I\) is the sum of each mass \(m\) times its distance \(r\) from the axis squared.
Angular Velocity (Constant Angular Acceleration): Final angular velocity \(\omega_f\) equals initial \(\omega_i\) plus angular acceleration \(\alpha\) times time \(t\).
Rotational Kinetic Energy: The energy of an object due to its rotation.
Angular Momentum: Angular momentum \(L\) is the moment of inertia \(I\) multiplied by the angular velocity \(\omega\).
Net Torque and Angular Momentum: Net external torque equals the rate of change of angular momentum.
Equilibrium Conditions: For a rigid body to be in equilibrium, the net force and net torque must both be zero.
Center of Gravity: The point where the total weight of the body can be considered to act.
Rotational Work: Work done by a constant torque \(\tau\) rotating an object through angle \(\theta\).
Total Mechanical Energy (Rolling): Sum of translational KE, rotational KE, and gravitational PE.
Conservation of Angular Momentum: If net external torque is zero, total angular momentum is conserved.
Practice quiz
A car travels along a circular track with a radius of $50 \text{ m}$. If the car covers an arc length of $150 \text{ m}$, what is its angular displacement?
- $3 \text{ rad}$
- $0.33 \text{ rad}$
- $7500 \text{ rad}$
- $150 \text{ rad}$
Answer: $3 \text{ rad}$
A rotating disk changes its angular position from $10 \text{ rad}$ to $70 \text{ rad}$ in $5 \text{ s}$. What is its average angular velocity?
- $12 \text{ rad/s}$
- $14 \text{ rad/s}$
- $16 \text{ rad/s}$
- $60 \text{ rad/s}$
Answer: $12 \text{ rad/s}$
A flywheel starts from rest and accelerates uniformly at $2 \text{ rad/s}^2$ for $10 \text{ s}$. What is its final angular velocity?
- $10 \text{ rad/s}$
- $20 \text{ rad/s}$
- $5 \text{ rad/s}$
- $0 \text{ rad/s}$
Answer: $20 \text{ rad/s}$
A wheel initially rotating at $5 \text{ rad/s}$ undergoes an angular acceleration of $3 \text{ rad/s}^2$. What is its angular displacement after $4 \text{ s}$?
- $20 \text{ rad}$
- $24 \text{ rad}$
- $44 \text{ rad}$
- $52 \text{ rad}$
Answer: $44 \text{ rad}$
A point on the rim of a spinning wheel is $0.5 \text{ m}$ from the center. If the wheel has an angular velocity of $10 \text{ rad/s}$, what is the tangential velocity of this point?
- $5 \text{ m/s}$
- $10 \text{ m/s}$
- $20 \text{ m/s}$
- $0.5 \text{ m/s}$
Answer: $5 \text{ m/s}$
A force of $20 \text{ N}$ is applied to a wrench at a distance of $0.3 \text{ m}$ from the pivot. If the force is applied perpendicular to the wrench, what is the magnitude of the torque produced?
- $6 \text{ N} \cdot \text{m}$
- $60 \text{ N} \cdot \text{m}$
- $0.6 \text{ N} \cdot \text{m}$
- $20.3 \text{ N} \cdot \text{m}$
Answer: $6 \text{ N} \cdot \text{m}$
A grinding wheel has a moment of inertia of $0.5 \text{ kg} \cdot \text{m}^2$. If a net torque of $10 \text{ N} \cdot \text{m}$ is applied to it, what is its angular acceleration?
- $5 \text{ rad/s}^2$
- $10 \text{ rad/s}^2$
- $20 \text{ rad/s}^2$
- $0.05 \text{ rad/s}^2$
Answer: $20 \text{ rad/s}^2$
A solid cylinder with a moment of inertia of $2 \text{ kg} \cdot \text{m}^2$ rotates at an angular velocity of $4 \text{ rad/s}$. What is its rotational kinetic energy?
- $8 \text{ J}$
- $16 \text{ J}$
- $32 \text{ J}$
- $4 \text{ J}$
Answer: $16 \text{ J}$
A figure skater has a moment of inertia of $3 \text{ kg} \cdot \text{m}^2$ when spinning at $5 \text{ rad/s}$. What is her angular momentum?
- $1.67 \text{ kg} \cdot \text{m}^2/\text{s}$
- $15 \text{ kg} \cdot \text{m}^2/\text{s}$
- $0.6 \text{ kg} \cdot \text{m}^2/\text{s}$
- $8 \text{ kg} \cdot \text{m}^2/\text{s}$
Answer: $15 \text{ kg} \cdot \text{m}^2/\text{s}$
A spinning ice skater pulls her arms in, reducing her moment of inertia from $4 \text{ kg} \cdot \text{m}^2$ to $1 \text{ kg} \cdot \text{m}^2$. If her initial angular velocity was $2 \text{ rad/s}$, what is her final angular velocity?
- $0.5 \text{ rad/s}$
- $2 \text{ rad/s}$
- $4 \text{ rad/s}$
- $8 \text{ rad/s}$
Answer: $8 \text{ rad/s}$
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