Refraction of Light: Lenses — Practice Quiz
A Physics cheat sheet for Refraction of Light: Lenses — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Index of Refraction: Ratio of speed of light in vacuum \(c\) to speed in material \(v\).
Snell's Law: Relates indices of refraction \(n\) and angles \(\theta\) for light crossing an interface.
Critical Angle: Angle of incidence \(\theta_c\) for total internal reflection (where \(n_1 > n_2\)).
Thin Lens Equation: Relates object distance \(d_o\), image distance \(d_i\), and focal length \(f\).
Magnification Equation: Relates magnification \(m\), image height \(h_i\), object height \(h_o\), and distances.
Lens Power: Refractive power \(P\) in diopters (D) is the inverse of focal length \(f\) in meters.
Telescope Magnification: Angular magnification \(M\) of a telescope with objective \(f_o\) and eyepiece \(f_e\).
Practice quiz
If the speed of light in a certain material is $2.0 \times 10^8 \text{ m/s}$, and the speed of light in a vacuum is $3.0 \times 10^8 \text{ m/s}$, what is the index of refraction of the material?
- $1.0$
- $1.33$
- $1.5$
- $2.0$
Answer: $1.5$
Light passes from air ($n_1 = 1.0$) into glass ($n_2 = 1.5$) with an angle of incidence of $30^\circ$. What is the angle of refraction?
- $19.5^\circ$
- $22.0^\circ$
- $30.0^\circ$
- $45.0^\circ$
Answer: $19.5^\circ$
A light ray travels from a medium with an index of refraction $n_1 = 1.6$ into a medium with an index of refraction $n_2 = 1.0$ (air). What is the critical angle for total internal reflection?
- $30.0^\circ$
- $38.7^\circ$
- $41.8^\circ$
- $45.0^\circ$
Answer: $38.7^\circ$
An object is placed $20 \text{ cm}$ in front of a converging lens with a focal length of $10 \text{ cm}$. Where will the image be formed?
- $5 \text{ cm}$
- $10 \text{ cm}$
- $15 \text{ cm}$
- $20 \text{ cm}$
Answer: $20 \text{ cm}$
An object $5 \text{ cm}$ tall is placed $30 \text{ cm}$ from a lens. If the image is formed $15 \text{ cm}$ on the other side of the lens, what is the magnitude of the image height?
- $2.5 \text{ cm}$
- $5.0 \text{ cm}$
- $7.5 \text{ cm}$
- $10.0 \text{ cm}$
Answer: $2.5 \text{ cm}$
A lens has a focal length of $50 \text{ cm}$. What is its refractive power in diopters?
- $0.5 \text{ D}$
- $1.0 \text{ D}$
- $2.0 \text{ D}$
- $4.0 \text{ D}$
Answer: $2.0 \text{ D}$
A simple refracting telescope has an objective lens with a focal length of $100 \text{ cm}$ and an eyepiece with a focal length of $5 \text{ cm}$. What is the angular magnification of the telescope?
- $5$
- $10$
- $15$
- $20$
Answer: $20$
For total internal reflection to occur, which of the following conditions must be met?
- Light must travel from a medium with a lower index of refraction to a medium with a higher index of refraction.
- The angle of incidence must be less than the critical angle.
- Light must travel from a medium with a higher index of refraction to a medium with a lower index of refraction, and the angle of incidence must be greater than the critical angle.
- The angle of refraction must be $90^\circ$.
Answer: Light must travel from a medium with a higher index of refraction to a medium with a lower index of refraction, and the angle of incidence must be greater than the critical angle.
An object is placed $15 \text{ cm}$ from a converging lens with a focal length of $10 \text{ cm}$. If the object is $3 \text{ cm}$ tall, what is the magnitude of the height of the image?
- $2 \text{ cm}$
- $3 \text{ cm}$
- $4.5 \text{ cm}$
- $6 \text{ cm}$
Answer: $6 \text{ cm}$
A person needs reading glasses with a power of $2.5 \text{ D}$. What is the focal length of these lenses?
- $25 \text{ cm}$
- $40 \text{ cm}$
- $50 \text{ cm}$
- $100 \text{ cm}$
Answer: $40 \text{ cm}$
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