Momentum and Impulse — Hard Practice Quiz
A Physics cheat sheet for Momentum and Impulse — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Impulse: The impulse \(\vec{J}\) is the product of the average force \(\vec{F}\) and the time interval \(\Delta t\).
Linear Momentum: The linear momentum \(\vec{p}\) is the product of mass \(m\) and velocity \(\vec{v}\).
Impulse-Momentum Theorem: The impulse applied to an object equals its change in momentum.
Conservation of Linear Momentum: The total linear momentum of an isolated system remains constant.
Center of Mass (Position): The coordinate \(x_{cm}\) of the center of mass for a two-particle system.
Velocity of Center of Mass: The velocity \(v_{cm}\) of the center of mass for a two-particle system.
Practice quiz
An object of mass $m$ is initially at rest. A constant force $F$ acts on it for a time $\Delta t$, giving it a final velocity $v_f$. If the same force $F$ were applied for a time $2\Delta t$ to an object of mass $2m$ that was initially moving with velocity $-v_f/2$, what would be the final velocity of the second object?
- $v_f/2$
- $v_f$
- $2v_f$
- $0$
Answer: $v_f/2$
Two particles, $m_1$ and $m_2$, are initially at rest. An internal explosion separates them. If $m_1 = 3m_2$, and $m_1$ moves with velocity $v_1$, what is the velocity of the center of mass of the system after the explosion?
- $0$
- $v_1$
- $v_1/2$
- $-v_1$
Answer: $0$
A system consists of two particles, $m_1$ and $m_2$, located at $x_1$ and $x_2$ respectively. The center of mass is at $x_{cm}$. If $m_1$ is moved to $x_1'$ such that the center of mass remains at $x_{cm}$, what must be the new position $x_2'$ of $m_2$?
- $\frac{m_1 (x_1 - x_1') + m_2 x_2}{m_2}$
- $\frac{m_1 (x_1' - x_1) + m_2 x_2}{m_2}$
- $\frac{m_1 x_1 + m_2 x_2 - x_1'}{m_2}$
- $\frac{m_1 x_1' + m_2 x_2}{m_1 + m_2}$
Answer: $\frac{m_1 (x_1 - x_1') + m_2 x_2}{m_2}$
A $1 \text{ kg}$ object moving at $10 \text{ m/s}$ collides head-on with a $2 \text{ kg}$ object moving at $5 \text{ m/s}$ in the opposite direction. After the collision, the $1 \text{ kg}$ object reverses direction and moves at $2 \text{ m/s}$. What is the impulse experienced by the $2 \text{ kg}$ object during the collision?
- $12 \text{ N} \cdot \text{s}$
- $8 \text{ N} \cdot \text{s}$
- $-12 \text{ N} \cdot \text{s}$
- $0 \text{ N} \cdot \text{s}$
Answer: $12 \text{ N} \cdot \text{s}$
A system of two particles has a total mass $M = m_1 + m_2$. If the velocity of the center of mass is $v_{cm}$, and particle $m_1$ has velocity $v_1$, what is the velocity of particle $m_2$ in terms of $M$, $m_1$, $v_{cm}$, and $v_1$?
- $\frac{M v_{cm} - m_1 v_1}{m_2}$
- $\frac{M v_{cm} + m_1 v_1}{m_2}$
- $\frac{m_1 v_1 - M v_{cm}}{m_2}$
- $\frac{M v_{cm}}{m_1 + m_2} - v_1$
Answer: $\frac{M v_{cm} - m_1 v_1}{m_2}$
Two identical carts, each of mass $m$, are moving towards each other with speeds $v$ and $2v$ respectively. They collide and stick together. What is the velocity of their center of mass after the collision?
- $-v/2$
- $v/2$
- $-v$
- $0$
Answer: $-v/2$
A rocket of total mass $M$ (including fuel) is initially at rest. It expels a small amount of fuel of mass $\Delta m$ at a constant exhaust velocity $v_e$ relative to the rocket. If the impulse on the rocket due to this expulsion is $J$, what is the change in the rocket's velocity?
- $J/(M - \Delta m)$
- $J/M$
- $J/\Delta m$
- $J/(M + \Delta m)$
Answer: $J/(M - \Delta m)$
Consider a system of two particles, $m_1$ and $m_2$. If $m_1$ is at $x_1$ and $m_2$ is at $x_2$, and $x_{cm}$ is their center of mass. If $m_1$ is moved to $x_1 + \delta x$, by what amount must $m_2$ be moved to keep the center of mass at the same position $x_{cm}$?
- $-\frac{m_1}{m_2} \delta x$
- $\frac{m_1}{m_2} \delta x$
- $-\frac{m_2}{m_1} \delta x$
- $\frac{m_2}{m_1} \delta x$
Answer: $-\frac{m_1}{m_2} \delta x$
An object of mass $m$ is initially at rest. It is subjected to a constant net force $F$ for a time $T$. What is the magnitude of the impulse delivered to the object during the first $T/2$ of the motion, in terms of its final momentum $p_f$ after time $T$?
- $p_f/2$
- $p_f$
- $2p_f$
- $p_f/4$
Answer: $p_f/2$
Two particles of masses $m$ and $3m$ are moving towards each other with speeds $v$ and $v/3$ respectively. They undergo a perfectly inelastic collision. What is the velocity of the combined mass after the collision?
- $0$
- $v/2$
- $v/4$
- $-v/4$
Answer: $0$
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