Momentum and Impulse — Practice Quiz
A Physics cheat sheet for Momentum and Impulse — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Impulse: The impulse \(\vec{J}\) is the product of the average force \(\vec{F}\) and the time interval \(\Delta t\).
Linear Momentum: The linear momentum \(\vec{p}\) is the product of mass \(m\) and velocity \(\vec{v}\).
Impulse-Momentum Theorem: The impulse applied to an object equals its change in momentum.
Conservation of Linear Momentum: The total linear momentum of an isolated system remains constant.
Center of Mass (Position): The coordinate \(x_{cm}\) of the center of mass for a two-particle system.
Velocity of Center of Mass: The velocity \(v_{cm}\) of the center of mass for a two-particle system.
Practice quiz
A $5 \text{ kg}$ object experiences a net force of $20 \text{ N}$ for $3 \text{ s}$. What is the magnitude of the impulse applied to the object?
- $60 \text{ N} \cdot \text{s}$
- $100 \text{ N} \cdot \text{s}$
- $15 \text{ N} \cdot \text{s}$
- $4 \text{ N} \cdot \text{s}$
Answer: $60 \text{ N} \cdot \text{s}$
A $2 \text{ kg}$ ball is moving with a velocity of $10 \text{ m/s}$ to the east. What is the magnitude of its linear momentum?
- $20 \text{ kg} \cdot \text{m/s}$
- $5 \text{ kg} \cdot \text{m/s}$
- $0.2 \text{ kg} \cdot \text{m/s}$
- $12 \text{ kg} \cdot \text{m/s}$
Answer: $20 \text{ kg} \cdot \text{m/s}$
A $0.5 \text{ kg}$ ball initially moving at $10 \text{ m/s}$ is hit by a bat, reversing its direction and increasing its speed to $15 \text{ m/s}$. What is the magnitude of the impulse delivered by the bat?
- $2.5 \text{ N} \cdot \text{s}$
- $7.5 \text{ N} \cdot \text{s}$
- $12.5 \text{ N} \cdot \text{s}$
- $1.25 \text{ N} \cdot \text{s}$
Answer: $12.5 \text{ N} \cdot \text{s}$
A $2 \text{ kg}$ cart moving at $3 \text{ m/s}$ collides head-on with a stationary $4 \text{ kg}$ cart. If the two carts stick together after the collision, what is their common final velocity?
- $1 \text{ m/s}$
- $0.5 \text{ m/s}$
- $1.5 \text{ m/s}$
- $2 \text{ m/s}$
Answer: $1 \text{ m/s}$
A $3 \text{ kg}$ mass is located at $x=0 \text{ m}$ and a $2 \text{ kg}$ mass is located at $x=5 \text{ m}$. Where is the center of mass of this two-particle system?
- $x=2 \text{ m}$
- $x=2.5 \text{ m}$
- $x=3 \text{ m}$
- $x=1 \text{ m}$
Answer: $x=2 \text{ m}$
A $1 \text{ kg}$ particle moves at $4 \text{ m/s}$ and a $3 \text{ kg}$ particle moves in the same direction at $2 \text{ m/s}$. What is the velocity of the center of mass of this system?
- $2.5 \text{ m/s}$
- $3 \text{ m/s}$
- $2.75 \text{ m/s}$
- $2.25 \text{ m/s}$
Answer: $2.5 \text{ m/s}$
To minimize the force experienced during a collision, one should:
- Decrease the time interval of the collision.
- Increase the time interval of the collision.
- Decrease the change in momentum.
- Increase the mass of the object.
Answer: Increase the time interval of the collision.
A $60 \text{ kg}$ person standing on ice throws a $0.5 \text{ kg}$ ball horizontally with a speed of $10 \text{ m/s}$. Assuming no friction, what is the recoil speed of the person?
- $0.083 \text{ m/s}$
- $0.167 \text{ m/s}$
- $0.5 \text{ m/s}$
- $0.042 \text{ m/s}$
Answer: $0.083 \text{ m/s}$
A $0.15 \text{ kg}$ baseball initially moving at $40 \text{ m/s}$ is caught by a catcher's mitt. If the ball comes to rest in $0.02 \text{ s}$, what is the magnitude of the average force exerted by the mitt on the ball?
- $300 \text{ N}$
- $150 \text{ N}$
- $600 \text{ N}$
- $75 \text{ N}$
Answer: $300 \text{ N}$
In an isolated system of two particles, if the first particle has a mass $m_1$ and velocity $v_1$, and the second particle has a mass $m_2$ and velocity $v_2$, what happens to the velocity of the center of mass ($v_{cm}$) if an internal force acts between the particles?
- $v_{cm}$ increases.
- $v_{cm}$ decreases.
- $v_{cm}$ remains constant.
- $v_{cm}$ changes direction.
Answer: $v_{cm}$ remains constant.
Select a subject
Select a subject from the left panel to begin exploring formulas.