Interference and Wave Nature of Light — Practice Quiz
A Physics cheat sheet for Interference and Wave Nature of Light — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Young's Double Slit (Bright Fringes): Angle \(\theta\) for constructive interference (bright fringes) with slit separation \(d\).
Where: \(m = 0, 1, 2, \dots\)
Young's Double Slit (Dark Fringes): Angle \(\theta\) for destructive interference (dark fringes) with slit separation \(d\).
Where: \(m = 0, 1, 2, \dots\)
Single Slit Diffraction (Dark Fringes): Angle \(\theta\) for destructive interference (dark fringes) with slit width \(W\).
Where: \(m = 1, 2, 3, \dots\) (Note: \(m \neq 0\))
Resolving Power (Rayleigh Criterion): Minimum angular separation \(\theta_{min}\) (in radians) to resolve two point sources with aperture diameter \(D\).
Diffraction Grating (Principal Maxima): Angle \(\theta\) for principal maxima with slit separation \(d\).
Where: \(m = 0, 1, 2, \dots\)
Practice quiz
A double-slit experiment uses light of wavelength $500 \text{ nm}$. The slits are separated by $0.1 \text{ mm}$. What is the angular position of the first-order bright fringe?
- $0.005 \text{ rad}$
- $0.010 \text{ rad}$
- $0.0025 \text{ rad}$
- $0.0075 \text{ rad}$
Answer: $0.005 \text{ rad}$
In a Young's double-slit experiment, light with a wavelength of $600 \text{ nm}$ passes through slits separated by $0.2 \text{ mm}$. What is the angular position of the first-order dark fringe ($m=0$ for the first dark fringe after the central bright fringe)?
- $0.0015 \text{ rad}$
- $0.0030 \text{ rad}$
- $0.00075 \text{ rad}$
- $0.0020 \text{ rad}$
Answer: $0.0015 \text{ rad}$
Monochromatic light of wavelength $550 \text{ nm}$ is incident on a single slit of width $0.05 \text{ mm}$. What is the angular position of the first minimum (dark fringe)?
- $0.011 \text{ rad}$
- $0.0055 \text{ rad}$
- $0.022 \text{ rad}$
- $0.008 \text{ rad}$
Answer: $0.011 \text{ rad}$
A telescope has an objective lens with a diameter of $10 \text{ cm}$. If it observes light with an average wavelength of $550 \text{ nm}$, what is the minimum angular separation (in radians) it can resolve according to the Rayleigh criterion?
- $6.71 \times 10^{-6} \text{ rad}$
- $5.50 \times 10^{-6} \text{ rad}$
- $1.22 \times 10^{-5} \text{ rad}$
- $1.10 \times 10^{-5} \text{ rad}$
Answer: $6.71 \times 10^{-6} \text{ rad}$
A diffraction grating has $5000$ lines per centimeter. When light of wavelength $600 \text{ nm}$ is incident normally on the grating, what is the angular position of the first-order principal maximum?
- $17.46^\circ$
- $30.00^\circ$
- $11.54^\circ$
- $23.58^\circ$
Answer: $17.46^\circ$
Which of the following formulas correctly describes the angular positions of bright fringes in a Young's double-slit experiment?
- $\sin \theta = m \frac{\lambda}{d}$
- $\sin \theta = (m + \frac{1}{2}) \frac{\lambda}{d}$
- $\sin \theta = m \frac{\lambda}{W}$
- $\theta_{min} \approx 1.22 \frac{\lambda}{D}$
Answer: $\sin \theta = m \frac{\lambda}{d}$
The formula $\sin \theta = m \frac{\lambda}{W}$ (for $m = 1, 2, 3, \dots$) describes the angular positions of:
- Bright fringes in a double-slit experiment.
- Dark fringes in a double-slit experiment.
- Dark fringes in a single-slit diffraction experiment.
- Principal maxima in a diffraction grating.
Answer: Dark fringes in a single-slit diffraction experiment.
In a Young's double-slit experiment, if the wavelength of light is increased, what happens to the angular separation between adjacent bright fringes?
- It increases.
- It decreases.
- It remains the same.
- It depends on the slit separation.
Answer: It increases.
To improve the resolving power of a telescope (i.e., decrease $\theta_{min}$), which of the following modifications would be most effective?
- Using light with a longer wavelength.
- Decreasing the diameter of the objective lens.
- Using light with a shorter wavelength.
- Increasing the distance to the observed objects.
Answer: Using light with a shorter wavelength.
Which of the following phenomena uses the same mathematical formula for its principal maxima as Young's double-slit experiment uses for its bright fringes?
- Single-slit diffraction dark fringes.
- Young's double-slit dark fringes.
- Diffraction grating principal maxima.
- Rayleigh criterion for resolving power.
Answer: Diffraction grating principal maxima.
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