Gravitation and Kepler's Laws — Practice Quiz
A Physics cheat sheet for Gravitation and Kepler's Laws — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Newton's Law of Universal Gravitation: The attractive force \(F_g\) between two masses \(m_1\), \(m_2\) separated by distance \(r\).
Where: \(G\) = Universal Gravitation Constant \((6.674 \times 10^{-11} N\cdot m^2/kg^2)\)
Gravitational Field Strength (Acceleration due to gravity): The field strength \(g\) at a distance \(r\) from a large mass \(M\).
Where: \(G\) = Universal Gravitation Constant
Kepler's Third Law (Law of Harmonies): The square of the orbital period \(T\) is proportional to the cube of the average orbital radius (or semi-major axis) \(r\).
Where: \(k\) = a constant that is the same for all objects orbiting the same central mass
Kepler's Third Law (General Form): The mathematical form derived from Newton's laws for an object of period \(T\) orbiting a mass \(M\) with radius \(r\) (for circular orbits).
Where: \(G\) = Universal Gravitation Constant; \(M\) = mass of the central body
Gravitational Potential: The potential energy per unit mass at a distance \(r\) from mass \(M\).
Where: \(G\) = Universal Gravitation Constant
Gravitational Potential Energy: The potential energy \(PE\) between two masses \(M\) and \(m\) separated by distance \(r\).
Where: \(G\) = Universal Gravitation Constant
Practice quiz
If the distance between two masses is doubled, how does the gravitational force between them change?
- It is halved.
- It is doubled.
- It is quartered.
- It is quadrupled.
Answer: It is quartered.
Two objects with masses $m_1 = 10 \text{ kg}$ and $m_2 = 20 \text{ kg}$ are separated by a distance of $r = 0.5 \text{ m}$. What is the gravitational force between them? Use $G = 6.674 \times 10^{-11} \text{ N} \cdot \text{m}^2/\text{kg}^2$.
- $5.34 \times 10^{-8} \text{ N}$
- $2.67 \times 10^{-8} \text{ N}$
- $1.07 \times 10^{-7} \text{ N}$
- $1.33 \times 10^{-7} \text{ N}$
Answer: $5.34 \times 10^{-8} \text{ N}$
If a planet's radius is halved while its mass remains constant, how does the gravitational field strength at its surface change?
- It is halved.
- It is doubled.
- It is quartered.
- It is quadrupled.
Answer: It is quadrupled.
A satellite orbits a planet of mass $M = 5.97 \times 10^{24} \text{ kg}$ at an altitude of $3.6 \times 10^7 \text{ m}$ from the planet's surface. If the planet's radius is $R = 6.37 \times 10^6 \text{ m}$, what is the gravitational field strength at the satellite's position? Use $G = 6.674 \times 10^{-11} \text{ N} \cdot \text{m}^2/\text{kg}^2$.
- $9.81 \text{ N/kg}$
- $0.22 \text{ N/kg}$
- $0.05 \text{ N/kg}$
- $1.62 \text{ N/kg}$
Answer: $0.22 \text{ N/kg}$
According to Kepler's Third Law, if a planet's average orbital radius around a star is increased by a factor of $4$, by what factor will its orbital period increase?
- $2$
- $4$
- $8$
- $16$
Answer: $8$
A satellite orbits Earth ($M = 5.97 \times 10^{24} \text{ kg}$) with an orbital period of $T = 86400 \text{ s}$ (1 day). Assuming a circular orbit, what is its orbital radius? Use $G = 6.674 \times 10^{-11} \text{ N} \cdot \text{m}^2/\text{kg}^2$ and $\pi = 3.14159$.
- $6.37 \times 10^6 \text{ m}$
- $4.22 \times 10^7 \text{ m}$
- $3.84 \times 10^8 \text{ m}$
- $1.50 \times 10^{11} \text{ m}$
Answer: $4.22 \times 10^7 \text{ m}$
Which of the following statements about gravitational potential ($V$) is true?
- Gravitational potential is always positive.
- Gravitational potential increases as distance from the mass $M$ increases.
- Gravitational potential is zero at the surface of a mass $M$.
- Gravitational potential is independent of the mass $M$.
Answer: Gravitational potential increases as distance from the mass $M$ increases.
Two masses $M$ and $m$ are initially at an infinite distance from each other. As they are brought closer to a finite distance $r$, their gravitational potential energy ($PE$) becomes:
- Positive and increasing.
- Negative and increasing.
- Positive and decreasing.
- Negative and decreasing.
Answer: Negative and decreasing.
Consider two masses $M$ and $m$ separated by a distance $r$. If the distance $r$ is increased, what happens to the magnitude of the gravitational force ($F_g$) and the gravitational potential energy ($PE$)?
- $F_g$ decreases, $PE$ increases.
- $F_g$ increases, $PE$ decreases.
- $F_g$ decreases, $PE$ decreases.
- $F_g$ increases, $PE$ increases.
Answer: $F_g$ decreases, $PE$ increases.
Planet A has mass $M_A$ and radius $R_A$. Planet B has mass $M_B = 2M_A$ and radius $R_B = 2R_A$. How does the gravitational field strength ($g$) on the surface of Planet B compare to that on Planet A?
- $g_B = \frac{1}{2} g_A$
- $g_B = g_A$
- $g_B = 2 g_A$
- $g_B = 4 g_A$
Answer: $g_B = \frac{1}{2} g_A$
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