Pythagorean Identities — Hard Practice Quiz
A Trigonometry cheat sheet for Pythagorean Identities — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Fundamental Pythagorean Identity
Tangent-Secant Identity
Cotangent-Cosecant Identity
Quotient Identities
Reciprocal Identity for Tangent and Cotangent
Reciprocal Identities
Practice quiz
Simplify the expression: $(\sec \alpha - \tan \alpha)(\sec \alpha + \tan \alpha)$.
- $1$
- $\sin^2 \alpha$
- $\cos^2 \alpha$
- $\tan^2 \alpha$
Answer: $1$
If $\sin \alpha = \frac{3}{5}$ and $\alpha$ is an acute angle, what is the value of $\tan \alpha$?
- $\frac{3}{4}$
- $\frac{4}{3}$
- $\frac{5}{3}$
- $\frac{4}{5}$
Answer: $\frac{3}{4}$
Express $\frac{1 - \sin^2 \alpha}{1 - \cos^2 \alpha}$ in terms of $\cot \alpha$.
- $\cot^2 \alpha$
- $\tan^2 \alpha$
- $\sec^2 \alpha$
- $\csc^2 \alpha$
Answer: $\cot^2 \alpha$
Simplify the expression: $\frac{\sin \alpha}{1 + \cos \alpha} + \frac{1 + \cos \alpha}{\sin \alpha}$.
- $2 \csc \alpha$
- $2 \sec \alpha$
- $2 \tan \alpha$
- $2 \cot \alpha$
Answer: $2 \csc \alpha$
If $\sec \alpha = x$, express $\sin \alpha$ in terms of $x$ (assume $\sin \alpha > 0$).
- $\frac{\sqrt{x^2 - 1}}{x}$
- $\frac{x}{\sqrt{x^2 - 1}}$
- $\frac{1}{x}$
- $\frac{x^2 - 1}{x}$
Answer: $\frac{\sqrt{x^2 - 1}}{x}$
Given $\tan \alpha = k$, express $\csc^2 \alpha$ in terms of $k$.
- $\frac{k^2 + 1}{k^2}$
- $\frac{k^2}{k^2 + 1}$
- $k^2 + 1$
- $\frac{1}{k^2 + 1}$
Answer: $\frac{k^2 + 1}{k^2}$
Simplify the expression: $(\sin \alpha + \cos \alpha)^2 + (\sin \alpha - \cos \alpha)^2$.
- $2$
- $1$
- $2 \sin^2 \alpha$
- $2 \cos^2 \alpha$
Answer: $2$
If $\sin \alpha + \cos \alpha = \frac{1}{2}$, what is the value of $\sin \alpha \cos \alpha$?
- $-\frac{3}{8}$
- $\frac{3}{8}$
- $\frac{1}{4}$
- $-\frac{1}{4}$
Answer: $-\frac{3}{8}$
Express $\frac{\sec \alpha - \cos \alpha}{\tan \alpha}$ in terms of $\sin \alpha$.
- $\sin \alpha$
- $\cos \alpha$
- $\tan \alpha$
- $\cot \alpha$
Answer: $\sin \alpha$
If $\tan \alpha = \frac{p}{q}$, express $\frac{\sin \alpha - \cos \alpha}{\sin \alpha + \cos \alpha}$ in terms of $p$ and $q$.
- $\frac{p - q}{p + q}$
- $\frac{p + q}{p - q}$
- $\frac{p^2 - q^2}{p^2 + q^2}$
- $\frac{p^2 + q^2}{p^2 - q^2}$
Answer: $\frac{p - q}{p + q}$
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