Product to Sum — Practice Quiz
A Trigonometry cheat sheet for Product to Sum — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Product of Sines
Product of Cosines
Product of Sine and Cosine
Practice quiz
Express $2 \sin(3x) \sin(5x)$ as a sum or difference of cosines.
- $\cos(2x) - \cos(8x)$
- $\cos(8x) - \cos(2x)$
- $\sin(8x) - \sin(2x)$
- $\sin(2x) - \sin(8x)$
Answer: $\cos(2x) - \cos(8x)$
Simplify the expression $\cos(7x) \cos(2x)$ using a product-to-sum formula.
- $\frac{1}{2}[\cos(5x) + \cos(9x)]$
- $\frac{1}{2}[\cos(9x) - \cos(5x)]$
- $\frac{1}{2}[\sin(9x) + \sin(5x)]$
- $\frac{1}{2}[\sin(9x) - \sin(5x)]
Answer: $\frac{1}{2}[\cos(5x) + \cos(9x)]$
Convert $\sin(4\theta) \cos(\theta)$ into a sum or difference of sines.
- $\frac{1}{2}[\sin(5\theta) + \sin(3\theta)]$
- $\frac{1}{2}[\sin(5\theta) - \sin(3\theta)]$
- $\frac{1}{2}[\cos(5\theta) + \cos(3\theta)]$
- $\frac{1}{2}[\cos(5\theta) - \cos(3\theta)]
Answer: $\frac{1}{2}[\sin(5\theta) + \sin(3\theta)]$
Which product expression is equivalent to $\frac{1}{2}[\cos(A) - \cos(B)]$?
- $\sin(\frac{A+B}{2}) \sin(\frac{B-A}{2})$
- $\cos(\frac{A+B}{2}) \cos(\frac{B-A}{2})$
- $\sin(\frac{A+B}{2}) \cos(\frac{B-A}{2})$
- $\cos(\frac{A+B}{2}) \sin(\frac{B-A}{2})$
Answer: $\sin(\frac{A+B}{2}) \sin(\frac{B-A}{2})$
Evaluate $\sin(75^{\circ}) \sin(15^{\circ})$.
- $\frac{1}{4}$
- $\frac{\sqrt{3}}{4}$
- $\frac{1}{2}$
- $0$
Answer: $\frac{1}{4}$
Simplify $2 \sin(x) \cos(y) - 2 \cos(x) \sin(y)$.
- $2 \sin(x-y)$
- $2 \cos(x-y)$
- $2 \sin(x+y)$
- $2 \cos(x+y)$
Answer: $2 \sin(x-y)$
Which of the following is the correct expansion of $\cos(A) \cos(B)$?
- $\frac{1}{2}[\cos(A-B) + \cos(A+B)]$
- $\frac{1}{2}[\cos(A-B) - \cos(A+B)]$
- $\frac{1}{2}[\sin(A+B) + \sin(A-B)]$
- $\frac{1}{2}[\sin(A+B) - \sin(A-B)]
Answer: $\frac{1}{2}[\cos(A-B) + \cos(A+B)]$
If $\sin(x) \cos(y) = \frac{1}{4}$ and $\sin(x+y) = \frac{3}{4}$, what is the value of $\sin(x-y)$?
- $-\frac{1}{4}$
- $\frac{1}{4}$
- $\frac{1}{2}$
- $-\frac{1}{2}$
Answer: $-\frac{1}{4}$
Simplify $\cos(\frac{5\pi}{12}) \cos(\frac{\pi}{12})$.
- $\frac{1}{4}$
- $\frac{\sqrt{3}}{4}$
- $\frac{1}{2}$
- $0$
Answer: $\frac{1}{4}$
Which expression is equivalent to $\sin(A) \sin(B) + \cos(A) \cos(B)$?
- $\cos(A-B)$
- $\cos(A+B)$
- $\sin(A-B)$
- $\sin(A+B)$
Answer: $\cos(A-B)$
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