Powers of Functions — Practice Quiz
A Trigonometry cheat sheet for Powers of Functions — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Sine Squared
Cosine Squared
Sine Cubed
Cosine Cubed
Practice quiz
What is the equivalent expression for $\sin^2 \alpha$?
- $\frac{1 - \cos(2\alpha)}{2}$
- $\frac{1 + \cos(2\alpha)}{2}$
- $\frac{3\sin \alpha - \sin(3\alpha)}{4}$
- $\frac{3\cos \alpha + \cos(3\alpha)}{4}$
Answer: $\frac{1 - \cos(2\alpha)}{2}$
Which of the following is the correct expansion for $\cos^2 \theta$?
- $\frac{1 - \cos(2\theta)}{2}$
- $\frac{1 + \cos(2\theta)}{2}$
- $\frac{3\sin \theta - \sin(3\theta)}{4}$
- $\frac{3\cos \theta + \cos(3\theta)}{4}$
Answer: $\frac{1 + \cos(2\theta)}{2}$
The expression $\sin^3 x$ can be rewritten as:
- $\frac{1 - \cos(2x)}{2}$
- $\frac{1 + \cos(2x)}{2}$
- $\frac{3\sin x - \sin(3x)}{4}$
- $\frac{3\cos x + \cos(3x)}{4}$
Answer: $\frac{3\sin x - \sin(3x)}{4}$
Simplify $\cos^3 \beta$ using the power-reduction formula.
- $\frac{1 - \cos(2\beta)}{2}$
- $\frac{1 + \cos(2\beta)}{2}$
- $\frac{3\sin \beta - \sin(3\beta)}{4}$
- $\frac{3\cos \beta + \cos(3\beta)}{4}$
Answer: $\frac{3\cos \beta + \cos(3\beta)}{4}$
If $\cos(2x) = 0.5$, what is the value of $\sin^2 x$?
- $0.25$
- $0.5$
- $0.75$
- $1$
Answer: $0.25$
Given $\cos(2\theta) = -\frac{1}{2}$, find the value of $\cos^2 \theta$.
- $\frac{1}{2}$
- $\frac{1}{4}$
- $\frac{3}{4}$
- $1$
Answer: $\frac{1}{4}$
Express $\sin(3\alpha)$ in terms of $\sin \alpha$ and $\sin^3 \alpha$.
- $3\sin \alpha - 4\sin^3 \alpha$
- $4\sin^3 \alpha - 3\sin \alpha$
- $\frac{3\sin \alpha + \sin^3 \alpha}{4}$
- $\frac{4\sin^3 \alpha + \sin(3\alpha)}{3}$
Answer: $3\sin \alpha - 4\sin^3 \alpha$
Which expression correctly represents $\cos(3x)$?
- $3\cos x - 4\cos^3 x$
- $4\cos^3 x - 3\cos x$
- $\frac{3\cos x - \cos^3 x}{4}$
- $\frac{4\cos^3 x + \cos(3x)}{3}$
Answer: $4\cos^3 x - 3\cos x$
Simplify the expression $\sin^2(3x) + \cos^2(3x)$.
- $1$
- $\cos(6x)$
- $\sin(6x)$
- $2$
Answer: $1$
Calculate the exact value of $\sin^3(\frac{\pi}{2})$.
- $0$
- $1$
- $-1$
- $\frac{1}{2}$
Answer: $1$
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