Half Angle — Practice Quiz
A Trigonometry cheat sheet for Half Angle — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Sine Half Angle
Cosine Half Angle
Tangent Half Angle
Practice quiz
What is the exact value of $\sin(15^\circ)$ using the half-angle formula?
- $\frac{\sqrt{2 - \sqrt{3}}}{2}$
- $\frac{\sqrt{2 + \sqrt{3}}}{2}$
- $\frac{\sqrt{3}}{2}$
- $\frac{1}{2}$
Answer: $\frac{\sqrt{2 - \sqrt{3}}}{2}$
If $\cos \alpha = \frac{3}{5}$ and $\alpha$ is in the fourth quadrant, what is $\cos(\frac{\alpha}{2})$?
- $\frac{2\sqrt{5}}{5}$
- -$ \frac{2\sqrt{5}}{5}$
- $\frac{\sqrt{5}}{5}$
- -$ \frac{\sqrt{5}}{5}$
Answer: -$ \frac{2\sqrt{5}}{5}$
Which of the following expressions is equivalent to $\tan(\frac{\theta}{2})$?
- $\frac{\sin \theta}{1 + \cos \theta}$
- $\frac{1 + \cos \theta}{\sin \theta}$
- $\frac{1 - \cos \theta}{1 + \sin \theta}$
- $\frac{\sin \theta}{1 - \cos \theta}$
Answer: $\frac{\sin \theta}{1 + \cos \theta}$
Given $\sin \alpha = \frac{4}{5}$ and $\alpha$ is in the second quadrant, find $\tan(\frac{\alpha}{2})$?
- $2$
- $\frac{1}{2}$
- -$ \frac{1}{2}$
- -$ \frac{2}{5}$
Answer: $2$
If $\sin(\frac{x}{2}) = \frac{1}{3}$, what is the value of $\cos x$?
- $\frac{7}{9}$
- $\frac{8}{9}$
- $\frac{1}{9}$
- -$ \frac{7}{9}$
Answer: $\frac{7}{9}$
Which of the following expressions is equivalent to $\frac{\sin(2\theta)}{1 + \cos(2\theta)}$?
- $\tan(\theta)$
- $\tan(2\theta)$
- $\sin(\theta)$
- $\cos(\theta)$
Answer: $\tan(\theta)$
If $\cos \theta = -\frac{1}{2}$ and $\theta$ is in the third quadrant, what is $\sin(\frac{\theta}{2})$?
- $\frac{1}{2}$
- -$ \frac{1}{2}$
- $\frac{\sqrt{3}}{2}$
- -$ \frac{\sqrt{3}}{2}$
Answer: $\frac{\sqrt{3}}{2}$
Simplify the expression $\frac{1 - \cos(4x)}{\sin(4x)}$.
- $\tan(2x)$
- $\tan(4x)$
- $\cot(2x)$
- $\sin(2x)$
Answer: $\tan(2x)$
Given $\cos \beta = 0.6$ and $\beta$ is an acute angle, find $\tan(\frac{\beta}{2})$?
- $0.5$
- $2$
- $0.8$
- $0.6$
Answer: $0.5$
Which of the following is the correct half-angle formula for $\cos(\frac{x}{2})$?
- $\pm\sqrt{\frac{1 + \cos x}{2}}$
- $\pm\sqrt{\frac{1 - \cos x}{2}}$
- $\frac{\sin x}{1 + \cos x}$
- $\frac{1 - \cos x}{\sin x}$
Answer: $\pm\sqrt{\frac{1 + \cos x}{2}}$
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