Double Angle — Hard Practice Quiz
A Trigonometry cheat sheet for Double Angle — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Sine Double Angle
Cosine Double Angle
Tangent Double Angle
Cotangent Double Angle
Practice quiz
Which of the following is the correct expansion of $\sin(4\alpha)$ in terms of $\sin \alpha$ and $\cos \alpha$?
- $4\sin\alpha\cos\alpha(\cos^2\alpha - \sin^2\alpha)$
- $2\sin\alpha\cos\alpha(1 - 2\sin^2\alpha)$
- $4\sin\alpha\cos\alpha(1 - 2\sin^2\alpha)$
- $2\sin(2\alpha)\cos(2\alpha)$
Answer: $4\sin\alpha\cos\alpha(\cos^2\alpha - \sin^2\alpha)$
Given $\tan \alpha = x$, which of the following correctly expresses $\cot(2\alpha)$ in terms of $x$?
- $\frac{1 - x^2}{2x}$
- $\frac{2x}{1 - x^2}$
- $\frac{x^2 - 1}{2x}$
- $\frac{2}{x(1 - x^2)}$
Answer: $\frac{1 - x^2}{2x}$
If $\cos(2\alpha) = \frac{1}{3}$, what is the value of $\sin^2 \alpha$?
- $\frac{1}{3}$
- $\frac{2}{3}$
- $\frac{1}{6}$
- $\frac{4}{3}$
Answer: $\frac{1}{3}$
Given that $\sin \alpha = \frac{3}{5}$ and $\alpha$ is an angle in the first quadrant, determine the value of $\tan(2\alpha)$.
- $\frac{24}{7}$
- $\frac{7}{24}$
- $\frac{12}{5}$
- $\frac{25}{7}$
Answer: $\frac{24}{7}$
Simplify the expression $\frac{\sin(2\alpha)}{1 + \cos(2\alpha)}$.
- $\tan\alpha$
- $\cot\alpha$
- $\sin\alpha$
- $\cos\alpha$
Answer: $\tan\alpha$
If $\cot \alpha = x$, which of the following expressions represents $\sin(2\alpha)$?
- $\frac{2x}{x^2 + 1}$
- $\frac{2}{x^2 + 1}$
- $\frac{x^2 - 1}{x^2 + 1}$
- $\frac{2x}{x^2 - 1}$
Answer: $\frac{2x}{x^2 + 1}$
The expression $\cos^4 \alpha - \sin^4 \alpha$ is equivalent to which of the following?
- $\cos(2\alpha)$
- $\sin(2\alpha)$
- $1$
- $\cos^2(2\alpha)$
Answer: $\cos(2\alpha)$
Given that $\sin \alpha + \cos \alpha = k$, express $\sin(2\alpha)$ in terms of $k$.
- $k^2 - 1$
- $1 - k^2$
- $2k$
- $\frac{k^2 - 1}{2}$
Answer: $k^2 - 1$
If $\tan(2\alpha) = \frac{4}{3}$ and $\alpha$ is an acute angle, what is the value of $\tan \alpha$?
- $\frac{1}{2}$
- $2$
- $\frac{1}{3}$
- $\frac{2}{3}$
Answer: $\frac{1}{2}$
Suppose $\cos \alpha = \frac{1}{\sqrt{10}}$ and $\alpha$ is an angle in the fourth quadrant. What is the value of $\sin(2\alpha)$?
- $-\frac{3}{5}$
- $\frac{3}{5}$
- $-\frac{3}{\sqrt{10}}$
- $\frac{3}{\sqrt{10}}$
Answer: $-\frac{3}{5}$
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