Algebra of Sets (Laws) — Hard Practice Quiz
A Set Theory cheat sheet for Algebra of Sets (Laws) — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Commutative laws: order does not matter
Associative law: grouping does not matter (the same holds for intersection)
Distributive law: intersection distributes over union
Distributive law: union distributes over intersection
Identity laws
Domination (null) laws
Idempotent laws
Complement laws
Double complement (involution) law
De Morgan law: the complement of a union is the intersection of the complements
De Morgan law: the complement of an intersection is the union of the complements
Absorption laws
Practice quiz
Simplify the set expression $( (A \cap B)^{c} \cup A )^{c}$.
- $\varnothing$
- $A$
- $B$
- $A^{c}$
Answer: $\varnothing$
Simplify the set expression $A \cap (B \cup A^{c})$.
- $A \cup B$
- $A \cap B$
- $A$
- $A^{c}$
Answer: $A \cap B$
Simplify the set expression $(A \cup B^{c})^{c} \cup (A^{c} \cap B^{c})$.
- $A$
- $B$
- $A^{c}$
- $U$
Answer: $A^{c}$
Given that $A \subseteq B$, simplify the set expression $(A \cup B^{c}) \cap B$.
- $A$
- $B$
- $\varnothing$
- $U$
Answer: $A$
Which of the following expressions is equivalent to $A \cup (A^{c} \cap B)$?
- $A \cap B$
- $A$
- $B$
- $A \cup B$
Answer: $A \cup B$
Simplify the set expression $(A \cap B) \cup (A \cap B^{c}) \cup (A^{c} \cap B)$.
- $A$
- $B$
- $A \cup B$
- $A \cap B$
Answer: $A \cup B$
If $A \cap B = \varnothing$ and $A \cup B = U$, what is the relationship between sets $A$ and $B$?
- $A = B$
- $A \subseteq B$
- $B = A^{c}$
- $A = \varnothing$
Answer: $B = A^{c}$
Simplify the set expression $(A \cup B) \cap (A \cup B^{c}) \cap (A^{c} \cup B)$.
- $A$
- $B$
- $A \cup B$
- $A \cap B$
Answer: $A \cap B$
Simplify the set expression $( (A \cup B^{c})^{c} \cup (A^{c} \cap B) )^{c}$.
- $A \cap B$
- $A^{c} \cup B$
- $A \cup B^{c}$
- $A^{c} \cap B^{c}$
Answer: $A \cup B^{c}$
Given that $A \cap B = \varnothing$ and $A \cup C = U$, simplify the set expression $(A \cup B) \cap (A^{c} \cup C)$.
- $A \cup B$
- $A \cap B$
- $B$
- $(A \cap C) \cup B$
Answer: $(A \cap C) \cup B$
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