Probability Rules — Practice Quiz
A Probability cheat sheet for Probability Rules — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Addition Rule (General)
Addition Rule (Mutually Exclusive)
Where: When \(P(A \cap B) = 0\)
Multiplication Rule (General)
Multiplication Rule (Independent)
Practice quiz
Given $P(X) = 0.6$, $P(Y) = 0.5$, and $P(X \cap Y) = 0.3$, what is $P(X \cup Y)$?
- $0.8$
- $0.9$
- $0.7$
- $0.6$
Answer: $0.8$
Events $M$ and $N$ are mutually exclusive. If $P(M) = 0.45$ and $P(N) = 0.3$, what is $P(M \cup N)$?
- $0.15$
- $0.75$
- $0.6$
- $0.9$
Answer: $0.75$
If $P(A) = 0.7$ and $P(B|A) = 0.6$, what is $P(A \cap B)$?
- $0.42$
- $0.1$
- $0.7$
- $0.6$
Answer: $0.42$
Events $E$ and $F$ are independent. If $P(E) = 0.8$ and $P(F) = 0.25$, what is $P(E \cap F)$?
- $0.2$
- $1.05$
- $0.55$
- $0.8$
Answer: $0.2$
For two events $A$ and $B$ to be mutually exclusive, which of the following must be true?
- $P(A \cap B) = P(A)P(B)$
- $P(A \cap B) = 0$
- $P(A \cup B) = 1$
- $P(A|B) = P(A)$
Answer: $P(A \cap B) = 0$
If events $C$ and $D$ are independent, which of the following statements is always true?
- $P(C \cup D) = P(C) + P(D)$
- $P(C|D) = 0$
- $P(C \cap D) = P(C)P(D)$
- $P(C) + P(D) = 1$
Answer: $P(C \cap D) = P(C)P(D)$
In a class, $60\%$ of students like Math ($M$) and $40\%$ like Science ($S$). If $20\%$ like both, what percentage of students like Math or Science?
- $100\%$
- $80\%$
- $60\%$
- $40\%$
Answer: $80\%$
A bag contains $5$ red balls and $3$ blue balls. If two balls are drawn without replacement, what is the probability that both are red?
- $\frac{25}{64}$
- $\frac{15}{56}$
- $\frac{20}{64}$
- $\frac{20}{56}$
Answer: $\frac{20}{56}$
Which statement is true about mutually exclusive and independent events?
- Mutually exclusive events are always independent.
- Independent events are always mutually exclusive.
- Events cannot be both mutually exclusive and independent unless one event has probability $0$.
- If $P(A) > 0$ and $P(B) > 0$, then mutually exclusive events are never independent.
Answer: If $P(A) > 0$ and $P(B) > 0$, then mutually exclusive events are never independent.
Given $P(A) = 0.5$, $P(B) = 0.4$, and $P(A \cup B) = 0.7$. Are events $A$ and $B$ independent?
- Yes, because $P(A \cap B) = P(A)P(B)$.
- No, because $P(A \cap B) \neq P(A)P(B)$.
- Yes, because $P(A \cup B) = P(A) + P(B)$.
- No, because $P(A \cup B) \neq P(A) + P(B)$.
Answer: Yes, because $P(A \cap B) = P(A)P(B)$.
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