Circles — Hard Practice Quiz
A Geometry cheat sheet for Circles — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Circumference
Where: \(r\) = radius, \(d\) = diameter
Area of Circle
Sector Area
Where: \(\theta\) = angle in radians
Arc Length
Where: \(\theta\) = angle in radians
Circular Segment Area
Practice quiz
A circular sector has an arc length $L_{arc}$ and a radius $r$. Which of the following expressions correctly represents the area of the circular segment formed by this sector?
- $\frac{1}{2}r L_{arc} - \frac{1}{2}r^2 \sin(\frac{L_{arc}}{r})$
- $\frac{1}{2}r^2(\frac{L_{arc}}{r} - \cos(\frac{L_{arc}}{r}))$
- $\frac{1}{2}r L_{arc} - r \sin(\frac{L_{arc}}{r})$
- $\frac{1}{2}r^2(\frac{L_{arc}}{r} - \tan(\frac{L_{arc}}{r}))$
Answer: $\frac{1}{2}r L_{arc} - \frac{1}{2}r^2 \sin(\frac{L_{arc}}{r})$
If the arc length of a circular sector is numerically equal to its radius $r$, what is the ratio of the sector's area to the total area of the circle?
- $\frac{1}{2\pi}$
- $\frac{1}{\pi}$
- $\frac{1}{4\pi}$
- $\frac{1}{2}$
Answer: $\frac{1}{2\pi}$
A circle has a circumference of $10\pi \text{ cm}$. A sector of this circle has an area of $15\pi \text{ cm}^2$. What is the arc length of this sector?
- $6\pi \text{ cm}$
- $5\pi \text{ cm}$
- $10\pi \text{ cm}$
- $3\pi \text{ cm}$
Answer: $6\pi \text{ cm}$
If the radius of a circle is increased by $20\%$ and the central angle of a sector within it is decreased by $10\%$, what is the percentage change in the sector's area?
- $29.6\%$ increase
- $20\%$ increase
- $10\%$ increase
- $15.2\%$ increase
Answer: $29.6\%$ increase
A circular segment is defined by an arc whose length is equal to the radius $r$ of the circle. What is the area of this segment?
- $\frac{1}{2}r^2(1 - \sin(1))$
- $\frac{1}{2}r^2(1 - \cos(1))$
- $\frac{1}{2}r^2(\pi - \sin(\pi))$
- $\frac{1}{2}r^2(1 - \frac{\pi}{2})$
Answer: $\frac{1}{2}r^2(1 - \sin(1))$
A circular sector has an area $A_{sector}$ and an arc length $L_{arc}$. Which expression correctly gives the radius $r$ of the circle?
- $\frac{2A_{sector}}{L_{arc}}$
- $\frac{A_{sector}}{2L_{arc}}$
- $\frac{L_{arc}}{2A_{sector}}$
- $\frac{A_{sector}L_{arc}}{2}$
Answer: $\frac{2A_{sector}}{L_{arc}}$
For what central angle $\theta$ (in radians, $0 < \theta \le 2\pi$) is the area of a circular sector equal to the area of the circular segment it defines?
- $\pi$
- $\frac{\pi}{2}$
- $2\pi$
- $1$
Answer: $\pi$
A circle has a circumference of $12\pi \text{ cm}$. A segment of this circle has an arc length of $4\pi \text{ cm}$. What is the area of this segment?
- $(12\pi - 9\sqrt{3}) \text{ cm}^2$
- $(12\pi - 18\sqrt{3}) \text{ cm}^2$
- $(6\pi - 9\sqrt{3}) \text{ cm}^2$
- $(18\pi - 9\sqrt{3}) \text{ cm}^2$
Answer: $(12\pi - 9\sqrt{3}) \text{ cm}^2$
Two concentric circles have arc lengths $L_1 = 3 \text{ cm}$ and $L_2 = 6 \text{ cm}$ for the same central angle. If the area of the larger sector is $18 \text{ cm}^2$, what is the area of the region between the two arcs?
- $13.5 \text{ cm}^2$
- $9 \text{ cm}^2$
- $12 \text{ cm}^2$
- $15 \text{ cm}^2$
Answer: $13.5 \text{ cm}^2$
For what central angle $\theta$ (in radians, $0 < \theta < 2\pi$) is the area of a circular segment exactly half the area of its corresponding sector?
- The solution to $\frac{1}{2}\theta = \sin\theta$
- $\frac{\pi}{3}$
- $\frac{\pi}{2}$
- The solution to $\theta = 2\sin\theta$
Answer: The solution to $\frac{1}{2}\theta = \sin\theta$
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