3D Shapes - Advanced — Hard Practice Quiz

A Geometry cheat sheet for 3D Shapes - Advanced — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.

Formulas & key concepts

Ellipsoid Volume

$$V = \frac{4}{3}\pi abc$$

Where: \(a, b, c\) = semi-axes

Torus Volume

$$V = 2\pi^2 Rr^2$$

Where: \(R\) = major radius, \(r\) = minor radius

Torus Surface Area

$$SA = 4\pi^2 Rr$$

Frustum Volume (Pyramid or Cone)

$$V = \frac{h}{3}(B_1 + B_2 + \sqrt{B_1 B_2})$$

Where: \(B_1, B_2\) = base areas

Regular Tetrahedron Volume

$$V = \frac{1}{12}a^3\sqrt{2}$$

Where: \(a\) = edge length

Cube

$$V = a^3, \quad SA = 6a^2, \quad d = a\sqrt{3}$$

Where: \(d\) = space diagonal

Practice quiz

  1. A cube has a space diagonal equal to the edge length of a regular tetrahedron. If the cube's volume is $V_C$, what is the tetrahedron's volume $V_T$ in terms of $V_C$?

    • $ \frac{\sqrt{6}}{4}V_C $
    • $ \frac{\sqrt{3}}{2}V_C $
    • $ \frac{\sqrt{2}}{3}V_C $
    • $ \frac{1}{2}V_C $

    Answer: $ \frac{\sqrt{6}}{4}V_C $

  2. A torus has a major radius $R$ and minor radius $r$. If its volume is $V$ and surface area is $SA$, express $R$ in terms of $V$, $SA$, and $\pi$.

    • $ R = \frac{SA^2}{8\pi^2 V} $
    • $ R = \frac{V SA}{2\pi^2} $
    • $ R = \frac{SA}{2\pi r} $
    • $ R = \frac{V}{2\pi^2 r^2} $

    Answer: $ R = \frac{SA^2}{8\pi^2 V} $

  3. An ellipsoid has semi-axes $a=2x$, $b=3x$, $c=x$. If its volume is equal to the volume of a cube with edge length $y$, what is $x$ in terms of $y$ and $\pi$?

    • $ x = \frac{y}{2\pi^{1/3}} $
    • $ x = \frac{y}{(6\pi)^{1/3}} $
    • $ x = \frac{y}{2\sqrt[3]{\pi}} $
    • $ x = \frac{y}{4\pi^{1/3}} $

    Answer: $ x = \frac{y}{2\pi^{1/3}} $

  4. A frustum of a pyramid has base areas $B_1$ and $B_2$. If $B_1$ is the surface area of a cube with edge length $L$, and $B_2$ is the surface area of a cube with edge length $2L$, and the frustum's height is $3L$, what is the frustum's volume in terms of $L$?

    • $ 42L^3 $
    • $ 36L^3 $
    • $ 54L^3 $
    • $ 28L^3 $

    Answer: $ 42L^3 $

  5. A torus has a major radius $R=2a$ and minor radius $r=a$. An ellipsoid has semi-axes $a, b=a, c=a$. What is the ratio of the torus volume to the ellipsoid volume?

    • $ 3\pi $
    • $ 2\pi $
    • $ 4\pi $
    • $ \frac{3}{2}\pi $

    Answer: $ 3\pi $

  6. A cube has a surface area $SA_C$. A torus has a major radius $R = \frac{SA_C}{24\pi}$ and minor radius $r = \frac{SA_C}{12\pi}$. What is the surface area of the torus $SA_T$ in terms of $SA_C$?

    • $ \frac{SA_C^2}{72} $
    • $ \frac{SA_C^2}{144} $
    • $ \frac{SA_C^2}{36} $
    • $ \frac{SA_C^2}{24\pi} $

    Answer: $ \frac{SA_C^2}{72} $

  7. A regular tetrahedron has edge length $a$. A frustum of a pyramid has base areas $B_1 = a^2$ and $B_2 = 4a^2$. If the frustum's height is such that its volume is equal to the tetrahedron's volume, what is the height $h$ of the frustum in terms of $a$?

    • $ \frac{a\sqrt{2}}{28} $
    • $ \frac{a\sqrt{2}}{14} $
    • $ \frac{a\sqrt{2}}{7} $
    • $ \frac{a\sqrt{2}}{42} $

    Answer: $ \frac{a\sqrt{2}}{28} $

  8. If the major radius $R$ of a torus is doubled and the minor radius $r$ is halved, how does its volume $V$ and surface area $SA$ change?

    • Volume is halved, Surface Area remains the same.
    • Volume remains the same, Surface Area is halved.
    • Both Volume and Surface Area are halved.
    • Volume is doubled, Surface Area remains the same.

    Answer: Volume is halved, Surface Area remains the same.

  9. An ellipsoid has semi-axes $a=2$, $b=3$, $c=4$. A frustum has base areas $B_1 = 4\pi$ and $B_2 = 9\pi$ and height $h=6$. What is the ratio of the ellipsoid's volume to the frustum's volume?

    • $ \frac{16}{19} $
    • $ \frac{32}{38} $
    • $ \frac{1}{2} $
    • $ \frac{2}{3} $

    Answer: $ \frac{16}{19} $

  10. A cube has a space diagonal $d$. A torus has a major radius $R = d$ and minor radius $r = \frac{d}{2\pi}$. What is the ratio of the cube's surface area to the torus's surface area?

    • $ \frac{1}{\pi} $
    • $ \frac{2}{\pi} $
    • $ \frac{1}{2\pi} $
    • $ \pi $

    Answer: $ \frac{1}{\pi} $

Select a subject

Select a subject from the left panel to begin exploring formulas.