Factoring Formulas — Hard Practice Quiz
A Algebra cheat sheet for Factoring Formulas — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Difference of Squares
Difference of Cubes
Sum of Cubes
Difference of Fourth Powers
Difference of Fifth Powers
Practice quiz
Factor $x^6 - y^6$ completely.
- $(x - y)(x + y)(x^2 + xy + y^2)(x^2 - xy + y^2)$
- $(x^3 - y^3)(x^3 + y^3)$
- $(x^2 - y^2)(x^4 + x^2y^2 + y^4)$
- $(x - y)(x + y)(x^2 + y^2)(x^2 - xy + y^2)$
Answer: $(x - y)(x + y)(x^2 + xy + y^2)(x^2 - xy + y^2)$
Given $a^3 - b^3 = 100$ and $a - b = 5$, find the value of $a^2 + b^2$. Round to two decimal places.
- $21.67
- $20.00
- $25.00
- $-5.00
Answer: $21.67
If $x^4 - y^4 = 240$ and $x^2 + y^2 = 30$, what is the value of $x^2 - y^2$?
- $8
- $7{,}200
- $-210
- $5
Answer: $8
Let $M = a+b$ and $N = a^2 - ab + b^2$. Which of the following expressions represents $a^3 + b^3$?
- $MN$
- $M+N$
- $M^2N$
- $M/N$
Answer: $MN$
Factor $x^6 - 64$ completely.
- $(x - 2)(x + 2)(x^2 + 2x + 4)(x^2 - 2x + 4)$
- $(x^3 - 8)(x^3 + 8)$
- $(x^2 - 4)(x^4 + 4x^2 + 16)$
- $(x - 2)(x^5 + 2x^4 + 4x^3 + 8x^2 + 16x + 32)$
Answer: $(x - 2)(x + 2)(x^2 + 2x + 4)(x^2 - 2x + 4)$
Calculate the exact value of $100^3 - 99^3$.
- $29{,}701
- $199
- $19{,}801
- $1{,}970{,}299
Answer: $29{,}701
Simplify the expression $\frac{x^4 - y^4}{x^3 + y^3}$, assuming $x \ne -y$.
- $\frac{(x - y)(x^2 + y^2)}{x^2 - xy + y^2}$
- $\frac{x^2 - y^2}{x - y}$
- $\frac{x^2 + y^2}{x^2 - xy + y^2}$
- $(x - y)(x^2 + y^2)$
Answer: $\frac{(x - y)(x^2 + y^2)}{x^2 - xy + y^2}$
Given $a+b=5$ and $a-b=3$, find the value of $a^2 - ab + b^2$. Round to two decimal places.
- $13.00
- $17.00
- $21.00
- $4.00
Answer: $13.00
Factor $x^8 - y^8$ completely.
- $(x - y)(x + y)(x^2 + y^2)(x^4 + y^4)$
- $(x^4 - y^4)(x^4 + y^4)$
- $(x^2 - y^2)(x^6 + x^4y^2 + x^2y^4 + y^6)$
- $(x - y)(x^7 + x^6y + x^5y^2 + x^4y^3 + x^3y^4 + x^2y^5 + xy^6 + y^7)$
Answer: $(x - y)(x + y)(x^2 + y^2)(x^4 + y^4)$
If $a^3 - b^3 = K$ and $a^3 + b^3 = L$, express $a^6 - b^6$ in terms of $K$ and $L$.
- $KL$
- $K+L$
- $K-L$
- $\frac{K}{L}$
Answer: $KL$
Select a subject
Select a subject from the left panel to begin exploring formulas.