Compound Interest — Hard Practice Quiz
A Financial Math cheat sheet for Compound Interest — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
The future value when interest compounds each period. \(A\) is the future value, \(P\) the principal, \(i = r/n\) the periodic rate, and \(N = nt\) the total number of periods, where \(r\) is the annual rate, \(n\) the compounding periods per year, and \(t\) the years.
The principal (present value) needed today to reach a future value \(A\) with compounding, where \(i = r/n\) is the periodic rate and \(N = nt\) the total number of periods.
The future value under continuous compounding, using \(e \approx 2.718\). \(P\) is the principal, \(r\) the annual rate, and \(t\) the time in years.
Practice quiz
An investor has two options for a \$10,000 investment over 7 years. Option A offers an annual interest rate of $5.5\%$ compounded quarterly. Option B offers an annual interest rate of $5.3\%$ compounded continuously. What is the difference in the future value between Option A and Option B, rounded to the nearest cent? (Option A - Option B)
- The difference is \$165.82
- The difference is \$54.96
- The difference is \$166.21
- The difference is \$-165.82
Answer: The difference is \$165.82
A future value of \$50,000 is desired in 10 years. The investment account offers an annual interest rate of $6\%$ compounded semi-annually. However, after 4 years, a withdrawal of \$10,000 will be made from the account. What initial principal must be invested today to achieve the \$50,000 target? Round to the nearest cent.
- \$35,577.88
- \$19,789.70
- \$33,220.55
- \$27,683.79
Answer: \$35,577.88
An investment of \$15,000 grows to \$25,000 in an account that compounds interest monthly at an annual rate of $4.8\%$. How many years did it take for the investment to reach this value? Round your answer to two decimal places.
- 10.66 years
- 0.91 years
- 127.96 years
- 10.90 years
Answer: 10.66 years
Consider an investment with a fixed principal $P$, annual rate $r$, and time $t$. If the number of compounding periods per year, $n$, increases indefinitely (approaching continuous compounding), what happens to the future value $A$?
- The future value $A$ approaches a finite limit, $Pe^{rt}$.
- The future value $A$ increases indefinitely.
- The future value $A$ decreases and approaches $P$.
- The future value $A$ remains constant, as $n$ only affects the periodic rate.
Answer: The future value $A$ approaches a finite limit, $Pe^{rt}$.
An investment offers an annual nominal rate of $7\%$ compounded daily (use $n=365$). Calculate the Effective Annual Rate (EAR) to four decimal places. Then, use this EAR to find the future value of a \$20,000 investment after 5 years, assuming interest is compounded annually at the EAR. Round the final future value to the nearest cent.
- \$28,380.40
- \$28,051.03
- \$31,218.44
- \$8,441,590,313,158,517,000,000,000,000,000,000,000,000,000,000,000,000,000,000.00
Answer: \$28,380.40
A principal of \$5,000 is invested for 3 years at an annual rate of $4\%$ compounded semi-annually. At the end of these 3 years, the entire accumulated amount is reinvested for another 5 years at an annual rate of $6\%$ compounded monthly. What is the final future value of the investment? Round to the nearest cent.
- \$7,595.12
- \$7,586.36
- \$7,535.30
- \$12,375.06
Answer: \$7,595.12
An initial investment of \$8,000 grows to \$12,000 in 6 years with continuous compounding. What is the annual interest rate $r$? Give your answer as a percentage rounded to two decimal places.
- 6.76\%
- 6.99\%
- 2.93\%
- 8.33\%
Answer: 6.76\%
A company needs to accumulate \$100,000 in 8 years for a new project. They plan to make an initial investment today in an account earning $5\%$ annual interest compounded quarterly. Additionally, they anticipate needing to deposit an extra \$15,000 into the account at the end of the 3rd year. What initial principal must the company invest today to meet their \$100,000 goal? Round to the nearest cent.
- \$54,275.78
- \$57,118.65
- \$59,703.36
- \$80,121.04
Answer: \$54,275.78
An investment is made with continuous compounding. If the annual interest rate $r$ is halved, how does the time $t$ required for the investment to double change?
- The time $t$ doubles.
- The time $t$ is halved.
- The time $t$ remains the same.
- The time $t$ increases by a factor of $\ln(2)$.
Answer: The time $t$ doubles.
An investment of \$20,000 grows to \$35,000 in 5 years. If the interest is compounded semi-annually, what is the annual interest rate $r$? Give your answer as a percentage rounded to two decimal places.
- 11.51\%
- 11.84\%
- 23.69\%
- 15.00\%
Answer: 11.51\%
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