Units and Measurements — Hard Practice Quiz
A Chemistry cheat sheet for Units and Measurements — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Temperature conversion: Celsius to Kelvin
Temperature conversion: Fahrenheit to Celsius
Temperature conversion: Celsius to Fahrenheit
Density = mass / volume
<table style="width:100%; border-collapse: collapse; font-size: 0.9em;"> <tr style="border-bottom: 1px solid #ccc;"><th>Quantity</th><th>Unit</th><th>Symbol</th></tr> <tr><td>Length</td><td>meter</td><td>m</td></tr> <tr><td>Mass</td><td>kilogram</td><td>kg</td></tr> <tr><td>Time</td><td>second</td><td>s</td></tr> <tr><td>Temperature</td><td>Kelvin</td><td>K</td></tr> <tr><td>Amount</td><td>mole</td><td>mol</td></tr> <tr><td>Current</td><td>Ampere</td><td>A</td></tr> <tr><td>Luminous int.</td><td>candela</td><td>cd</td></tr> </table>
<table style="width:100%; border-collapse: collapse; font-size: 0.9em;"> <tr style="border-bottom: 1px solid #ccc;"><th>Prefix</th><th>Symbol</th><th>Factor</th></tr> <tr><td>Peta</td><td>P</td><td>10<sup>15</sup></td></tr> <tr><td>Tera</td><td>T</td><td>10<sup>12</sup></td></tr> <tr><td>Giga</td><td>G</td><td>10<sup>9</sup></td></tr> <tr><td>Mega</td><td>M</td><td>10<sup>6</sup></td></tr> <tr><td>Kilo</td><td>k</td><td>10<sup>3</sup></td></tr> <tr><td>Deci</td><td>d</td><td>10<sup>-1</sup></td></tr> <tr><td>Centi</td><td>c</td><td>10<sup>-2</sup></td></tr> <tr><td>Milli</td><td>m</td><td>10<sup>-3</sup></td></tr> <tr><td>Micro</td><td>μ</td><td>10<sup>-6</sup></td></tr> <tr><td>Nano</td><td>n</td><td>10<sup>-9</sup></td></tr> <tr><td>Pico</td><td>p</td><td>10<sup>-12</sup></td></tr> <tr><td>Femto</td><td>f</td><td>10<sup>-15</sup></td></tr> </table>
Practice quiz
A chemical reaction occurs at $77 ^\circ F$. What is this temperature in Kelvin?
- $298.15 \text{ K}$
- $250.15 \text{ K}$
- $350.15 \text{ K}$
- $273.15 \text{ K}$
Answer: $298.15 \text{ K}$
A material has a density of $2.7 \text{ g/cm}^3$. What is the mass, in kilograms, of $0.05 \text{ m}^3$ of this material?
- $135 \text{ kg}$
- $13.5 \text{ kg}$
- $1350 \text{ kg}$
- $1.35 \text{ kg}$
Answer: $135 \text{ kg}$
A sample of liquid has a mass of $5.4 \text{ kg}$ and a density of $0.9 \text{ g/mL}$. What is its volume in liters? (Note: $1 \text{ mL} = 1 \text{ cm}^3$).
- $6 \text{ L}$
- $0.6 \text{ L}$
- $60 \text{ L}$
- $54 \text{ L}$
Answer: $6 \text{ L}$
For most substances, if the temperature increases, causing the substance to expand, how does its density change, assuming its mass remains constant?
- It decreases.
- It increases.
- It remains constant.
- It depends on the specific heat capacity.
Answer: It decreases.
Given the density formula $d = \frac{m}{V}$, if the mass $m$ of an object is equivalent to the mass of a liquid with density $d_L$ and volume $V_L$, express the volume $V$ of the object in terms of $d$, $d_L$, and $V_L$.
- $V = \frac{d_L V_L}{d}$
- $V = \frac{d V_L}{d_L}$
- $V = d d_L V_L$
- $V = \frac{d}{d_L V_L}$
Answer: $V = \frac{d_L V_L}{d}$
Two objects, A and B, have the same mass. Object A has a volume $V_A$ and density $d_A$. Object B has a volume $V_B = 3V_A$. What is the ratio of their densities, $d_A/d_B$?
- $3$
- $1/3$
- $9$
- $1$
Answer: $3$
A temperature change of $1.5 \text{ kK}$ (kilokelvin) is observed. What is this temperature change in degrees Celsius?
- $1500 ^\circ C$
- $1.5 ^\circ C$
- $150 ^\circ C$
- $1500 + 273.15 ^\circ C$
Answer: $1500 ^\circ C$
A block of material has a mass of $1.2 \text{ Mg}$ (megagrams) and a density of $2.0 \text{ g/cm}^3$. What is its volume in cubic meters?
- $0.6 \text{ m}^3$
- $600 \text{ m}^3$
- $6 \times 10^{-4} \text{ m}^3$
- $1.2 \times 10^6 \text{ m}^3$
Answer: $0.6 \text{ m}^3$
Density is a derived SI unit. Which combination of SI base units correctly defines density?
- kilogram per cubic meter
- gram per cubic centimeter
- kilogram per liter
- gram per milliliter
Answer: kilogram per cubic meter
At what numerical value do the Celsius and Fahrenheit temperature scales read the same?
- $-40$
- $0$
- $32$
- $100$
Answer: $-40$
Select a subject
Select a subject from the left panel to begin exploring formulas.