Kinetics — Hard Practice Quiz
A Chemistry cheat sheet for Kinetics — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Reaction Rate: Relates the rates of disappearance of reactants and appearance of products for \(aA + bB \rightarrow cC + dD\).
Where: \(a,b,c,d\) = stoichiometric coefficients
Rate Law: Relates reaction rate to rate constant and concentrations.
Where: \(k\) = rate constant, \(m,n\) = reaction orders
First-Order Integrated Rate Law: Relates concentration to time for a first-order reaction.
Where: \([A]_t\) = conc. at time t, \([A]_0\) = initial conc.
Second-Order Integrated Rate Law: Relates concentration to time for a second-order reaction.
Half-Life (First-Order): Time required for concentration to decrease by half.
Where: \(t_{1/2}\) = half-life
Arrhenius Equation: Relates rate constant to activation energy and temperature.
Where: \(A\) = frequency factor, \(E_a\) = activation energy, \(R\) = gas constant, \(T\) = temperature
Linear Arrhenius Equation: Linear form used to determine activation energy graphically.
Practice quiz
A first-order reaction has a half-life of $150 \text{ s}$. If the initial concentration of reactant $A$ is $0.80 \text{ M}$, what percentage of $A$ remains after $450 \text{ s}$?
- $6.25\%$
- $12.5\%$
- $25.0\%$
- $33.3\%$
Answer: $12.5\%$
For a reaction $2A \rightarrow B$, the initial rate is $0.020 \text{ M/s}$ when $[A]_0 = 0.10 \text{ M}$. If the reaction is second-order with respect to $A$, how long will it take for the concentration of $A$ to decrease to $0.025 \text{ M}$?
- $5 \text{ s}$
- $10 \text{ s}$
- $15 \text{ s}$
- $20 \text{ s}$
Answer: $15 \text{ s}$
A reaction $A + B \rightarrow C$ is first-order in $A$ and first-order in $B$. Its activation energy is $50 \text{ kJ/mol}$. If the temperature is increased from $298 \text{ K}$ to $308 \text{ K}$, by what factor does the initial rate of reaction increase, assuming $[A]$ and $[B]$ are constant? ($R = 8.314 \text{ J/(mol} \cdot \text{K)}$)
- $1.5$ times
- $1.9$ times
- $2.5$ times
- $3.0$ times
Answer: $1.9$ times
For the reaction $2NO_2(g) \rightarrow 2NO(g) + O_2(g)$, the rate constant $k$ is $0.54 \text{ M}^{-1}\text{s}^{-1}$ at $300 \text{ K}$. If the initial concentration of $NO_2$ is $0.20 \text{ M}$, what is the rate of formation of $O_2$ after $10 \text{ s}$?
- $0.0012 \text{ M/s}$
- $0.0025 \text{ M/s}$
- $0.0050 \text{ M/s}$
- $0.0100 \text{ M/s}$
Answer: $0.0025 \text{ M/s}$
The rate constant for a first-order reaction is $2.0 \times 10^{-4} \text{ s}^{-1}$ at $25^\circ\text{C}$ and $8.0 \times 10^{-4} \text{ s}^{-1}$ at $40^\circ\text{C}$. What is the half-life of this reaction at $50^\circ\text{C}$? ($R = 8.314 \text{ J/(mol} \cdot \text{K)}$)
- $173 \text{ s}$
- $245 \text{ s}$
- $369 \text{ s}$
- $481 \text{ s}$
Answer: $369 \text{ s}$
Consider two reactions, one first-order and one second-order, both with the same initial concentration $[A]_0$ and the same initial rate. If the concentration of $A$ is halved, how does the ratio of their new half-lives ($t_{1/2, \text{second-order}} / t_{1/2, \text{first-order}}$) change compared to their initial half-lives?
- It remains the same.
- It doubles.
- It halves.
- It quadruples.
Answer: It doubles.
For the reaction $2X + Y \rightarrow Z$, the following initial rate data were collected: \n\n| Experiment | $[X]_0$ (M) | $[Y]_0$ (M) | Initial Rate (M/s) |\n| :--------- | :---------- | :---------- | :----------------- |\n| 1 | $0.10$ | $0.10$ | $1.0 \times 10^{-3}$ |\n| 2 | $0.20$ | $0.10$ | $4.0 \times 10^{-3}$ |\n| 3 | $0.10$ | $0.20$ | $2.0 \times 10^{-3}$ |\n\nWhat is the rate of disappearance of $Y$ when $[X] = 0.05 \text{ M}$ and $[Y] = 0.05 \text{ M}$?
- $6.25 \times 10^{-5} \text{ M/s}$
- $1.25 \times 10^{-4} \text{ M/s}$
- $2.50 \times 10^{-4} \text{ M/s}$
- $5.00 \times 10^{-4} \text{ M/s}$
Answer: $1.25 \times 10^{-4} \text{ M/s}$
A reaction $A \rightarrow 2B$ is studied. The initial concentration of $A$ is $0.50 \text{ M}$. After $100 \text{ s}$, the concentration of $B$ is $0.60 \text{ M}$. If the reaction is known to be either first-order or second-order with respect to $A$, what is the rate constant $k$ for this reaction?
- $0.00916 \text{ s}^{-1}$ (first-order)
- $0.0300 \text{ M}^{-1}\text{s}^{-1}$ (second-order)
- $0.00600 \text{ s}^{-1}$ (first-order)
- $0.0150 \text{ M}^{-1}\text{s}^{-1}$ (second-order)
Answer: $0.00916 \text{ s}^{-1}$ (first-order)
A catalyst lowers the activation energy of a reaction from $75 \text{ kJ/mol}$ to $50 \text{ kJ/mol}$ at $300 \text{ K}$. By what factor does the rate constant increase due to the catalyst? ($R = 8.314 \text{ J/(mol} \cdot \text{K)}$)
- $1.5 \times 10^2$
- $2.3 \times 10^3$
- $2.3 \times 10^4$
- $1.5 \times 10^5$
Answer: $2.3 \times 10^4$
For a certain first-order reaction, a plot of $\ln k$ versus $1/T$ yields a straight line with a slope of $-8.5 \times 10^3 \text{ K}$. If the half-life of the reaction at $350 \text{ K}$ is $120 \text{ s}$, what is the value of the frequency factor $A$? ($R = 8.314 \text{ J/(mol} \cdot \text{K)}$)
- $1.0 \times 10^6 \text{ s}^{-1}$
- $5.0 \times 10^7 \text{ s}^{-1}$
- $1.0 \times 10^8 \text{ s}^{-1}$
- $5.0 \times 10^8 \text{ s}^{-1}$
Answer: $1.0 \times 10^8 \text{ s}^{-1}$
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