Electrochemistry — Hard Practice Quiz
A Chemistry cheat sheet for Electrochemistry — every key formula with its symbols defined — plus a hard-level practice quiz to test recall.
Formulas & key concepts
Gibbs Free Energy and Cell Potential: Relates free energy change to cell potential.
Where: \(n\) = moles of electrons, \(F\) = Faraday constant (96,485 C/mol), \(E\) = cell potential
Standard Free Energy and Standard Cell Potential: Relationship under standard conditions.
Where: \(E^\circ\) = standard cell potential
Cell Potential and Equilibrium Constant: Relates standard cell potential to equilibrium constant.
Where: \(R\) = gas constant, \(T\) = temperature, \(K\) = equilibrium constant
Maximum Electrical Work: Maximum useful work obtainable from a voltaic cell.
Where: \(w_{\text{max}}\) = maximum work
Free Energy Under Nonstandard Conditions: General relationship involving reaction quotient.
Where: \(Q\) = reaction quotient
Nernst Equation: Relates cell potential to concentrations (natural log form).
Nernst Equation (Base-10): Relates cell potential to concentrations (base-10 log form).
Nernst Equation Simplified: Simplified form at 298 K for practical calculations.
Where: Valid at \(T = 298\text{ K}\)
Practice quiz
If an electrochemical reaction is spontaneous under standard conditions, which of the following statements is true regarding its standard cell potential ($E^\circ$) and equilibrium constant ($K$)?
- $E^\circ > 0$ and $K > 1$
- $E^\circ < 0$ and $K < 1$
- $E^\circ > 0$ and $K < 1$
- $E^\circ < 0$ and $K > 1$
Answer: $E^\circ > 0$ and $K > 1$
Which of the following expressions correctly relates the equilibrium constant ($K$) to the standard Gibbs free energy change ($\Delta G^\circ$) for an electrochemical reaction?
- $K = e^{-\frac{\Delta G^\circ}{RT}}$
- $K = e^{\frac{\Delta G^\circ}{RT}}$
- $K = \ln(-\frac{\Delta G^\circ}{RT})$
- $K = -\frac{\Delta G^\circ}{RT}$
Answer: $K = e^{-\frac{\Delta G^\circ}{RT}}$
Consider a redox reaction with a constant standard Gibbs free energy change ($\Delta G^\circ$). If the number of electrons transferred ($n$) is doubled, how would the standard cell potential ($E^\circ$) and the equilibrium constant ($K$) be affected?
- $E^\circ$ halves, $K$ remains unchanged.
- $E^\circ$ doubles, $K$ remains unchanged.
- $E^\circ$ halves, $K$ is squared.
- $E^\circ$ doubles, $K$ is squared.
Answer: $E^\circ$ halves, $K$ remains unchanged.
A voltaic cell operates at $298 \text{ K}$ with a standard cell potential $E^\circ = 1.10 \text{ V}$. If the reaction quotient $Q = 100$ and $n=2$, calculate the non-standard Gibbs free energy change ($\Delta G$) for the reaction. Use $F = 96485 \text{ C/mol}$.
- $-200.9 \text{ kJ/mol}$
- $-212.3 \text{ kJ/mol}$
- $-190.5 \text{ kJ/mol}$
- $-220.0 \text{ kJ/mol}$
Answer: $-200.9 \text{ kJ/mol}$
For an electrochemical cell, if the maximum electrical work ($w_{\text{max}}$) obtainable is negative, what does this imply about the spontaneity of the reaction and the cell potential ($E_{\text{cell}}$)?
- The reaction is spontaneous, and $E_{\text{cell}} > 0$.
- The reaction is non-spontaneous, and $E_{\text{cell}} < 0$.
- The reaction is at equilibrium, and $E_{\text{cell}} = 0$.
- The reaction is spontaneous, and $E_{\text{cell}} < 0$.
Answer: The reaction is spontaneous, and $E_{\text{cell}} > 0$.
Which of the following expressions correctly solves for the reaction quotient ($Q$) from the natural logarithm form of the Nernst equation?
- $Q = e^{\frac{nF(E^\circ - E)}{RT}}$
- $Q = e^{\frac{RT(E - E^\circ)}{nF}}$
- $Q = \ln(\frac{nF(E^\circ - E)}{RT})$
- $Q = \frac{nF(E^\circ - E)}{RT}$
Answer: $Q = e^{\frac{nF(E^\circ - E)}{RT}}$
At $298 \text{ K}$, an electrochemical reaction has a non-standard Gibbs free energy change $\Delta G = -150 \text{ kJ/mol}$ when the reaction quotient $Q = 0.1$. If $n=2$, calculate the equilibrium constant ($K$) for this reaction. Use $R = 8.314 \text{ J/(mol} \cdot \text{K)}$.
- $2.5 \times 10^{25}$
- $1.2 \times 10^{24}$
- $5.8 \times 10^{23}$
- $3.1 \times 10^{26}$
Answer: $2.5 \times 10^{25}$
For an electrochemical cell with a positive standard cell potential ($E^\circ > 0$) and a reaction quotient $Q > 1$, how does an increase in temperature ($T$) affect the non-standard cell potential ($E$)?
- $E$ decreases.
- $E$ increases.
- $E$ remains unchanged.
- $E$ first increases, then decreases.
Answer: $E$ decreases.
A reaction at $298 \text{ K}$ has an equilibrium constant $K = 1.0 \times 10^{10}$ and involves the transfer of $n=3$ electrons. Calculate the maximum electrical work ($w_{\text{max}}$) that can be obtained from this cell under standard conditions. Use $R = 8.314 \text{ J/(mol} \cdot \text{K)}$ and $F = 96485 \text{ C/mol}$.
- $-57.0 \text{ kJ/mol}$
- $-62.5 \text{ kJ/mol}$
- $-48.2 \text{ kJ/mol}$
- $-71.8 \text{ kJ/mol}$
Answer: $-57.0 \text{ kJ/mol}$
What is the relationship between the Gibbs free energy change ($\Delta G$) and the cell potential ($E$) when an electrochemical cell reaches equilibrium?
- $\Delta G = 0$ and $E = 0$.
- $\Delta G = \Delta G^\circ$ and $E = E^\circ$.
- $\Delta G < 0$ and $E > 0$.
- $\Delta G > 0$ and $E < 0$.
Answer: $\Delta G = 0$ and $E = 0$.
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