Electrochemistry — Practice Quiz
A Chemistry cheat sheet for Electrochemistry — every key formula with its symbols defined — plus a medium-level practice quiz to test recall.
Formulas & key concepts
Gibbs Free Energy and Cell Potential: Relates free energy change to cell potential.
Where: \(n\) = moles of electrons, \(F\) = Faraday constant (96,485 C/mol), \(E\) = cell potential
Standard Free Energy and Standard Cell Potential: Relationship under standard conditions.
Where: \(E^\circ\) = standard cell potential
Cell Potential and Equilibrium Constant: Relates standard cell potential to equilibrium constant.
Where: \(R\) = gas constant, \(T\) = temperature, \(K\) = equilibrium constant
Maximum Electrical Work: Maximum useful work obtainable from a voltaic cell.
Where: \(w_{\text{max}}\) = maximum work
Free Energy Under Nonstandard Conditions: General relationship involving reaction quotient.
Where: \(Q\) = reaction quotient
Nernst Equation: Relates cell potential to concentrations (natural log form).
Nernst Equation (Base-10): Relates cell potential to concentrations (base-10 log form).
Nernst Equation Simplified: Simplified form at 298 K for practical calculations.
Where: Valid at \(T = 298\text{ K}\)
Practice quiz
For a spontaneous electrochemical cell, what is the sign of the Gibbs free energy change, $\Delta G$, and the cell potential, $E$?
- $\Delta G < 0$ and $E > 0$
- $\Delta G > 0$ and $E < 0$
- $\Delta G < 0$ and $E < 0$
- $\Delta G > 0$ and $E > 0$
Answer: $\Delta G < 0$ and $E > 0$
Calculate the standard Gibbs free energy change, $\Delta G^\circ$, for a reaction where $n=2$ moles of electrons are transferred and the standard cell potential, $E^\circ$, is $1.10 \text{ V}$. Use $F = 96485 \text{ C/mol}$.
- $-212.267 \text{ kJ/mol}$
- $212.267 \text{ kJ/mol}$
- $-106.134 \text{ kJ/mol}$
- $106.134 \text{ kJ/mol}$
Answer: $-212.267 \text{ kJ/mol}$
If the standard cell potential, $E^\circ$, for an electrochemical reaction is positive, what can be concluded about the equilibrium constant, $K$, for the reaction at $298 \text{ K}$?
- $K > 1$
- $K < 1$
- $K = 1$
- $K = 0$
Answer: $K > 1$
A voltaic cell operates with a cell potential, $E_{\text{cell}}$, of $0.80 \text{ V}$ and transfers $3$ moles of electrons. What is the maximum electrical work, $w_{\text{max}}$, that can be obtained from this cell? Use $F = 96485 \text{ C/mol}$.
- $-231.564 \text{ kJ}$
- $231.564 \text{ kJ}$
- $-77.188 \text{ kJ}$
- $77.188 \text{ kJ}$
Answer: $-231.564 \text{ kJ}$
According to the Nernst equation, if the reaction quotient, $Q$, for a voltaic cell is increased, what happens to the cell potential, $E$?
- $E$ increases
- $E$ decreases
- $E$ remains the same
- $E$ becomes equal to $E^\circ$
Answer: $E$ decreases
A cell has a standard potential, $E^\circ$, of $0.50 \text{ V}$. If $n=2$ and the reaction quotient, $Q$, is $100$, what is the cell potential, $E$, at $298 \text{ K}$?
- $0.4408 \text{ V}$
- $0.5592 \text{ V}$
- $0.50 \text{ V}$
- $0.3816 \text{ V}$
Answer: $0.4408 \text{ V}$
At equilibrium, what is the relationship between $\Delta G$ and $\Delta G^\circ$?
- $\Delta G = \Delta G^\circ$
- $\Delta G = 0$, so $\Delta G^\circ = -RT \ln K$
- $\Delta G^\circ = 0$, so $\Delta G = RT \ln Q$
- $\Delta G = \Delta G^\circ + RT \ln K$
Answer: $\Delta G = 0$, so $\Delta G^\circ = -RT \ln K$
The simplified form of the Nernst equation, $E = E^\circ - \frac{0.0592\text{ V}}{n} \log Q$, is valid under what specific condition?
- Only at standard pressure
- Only at $0^\circ \text{ C}$
- Only at $298 \text{ K}$
- Only when $Q=1$
Answer: Only at $298 \text{ K}$
If the equilibrium constant, $K$, for a reaction is $1.0 \times 10^5$ at $298 \text{ K}$ and $n=1$, calculate $\Delta G^\circ$. Use $R = 8.314 \text{ J/(mol} \cdot \text{K)}$.
- $-28.5 \text{ kJ/mol}$
- $28.5 \text{ kJ/mol}$
- $-14.2 \text{ kJ/mol}$
- $14.2 \text{ kJ/mol}$
Answer: $-28.5 \text{ kJ/mol}$
In the Nernst equation, what does $Q$ represent?
- The equilibrium constant
- The standard cell potential
- The reaction quotient
- The Gibbs free energy
Answer: The reaction quotient
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